No. Ironically you are wrong on all counts.I have a the original CanaKit PSU rated at:
Output voltage = 5.1V
Output current = 3.5A
Power = 17.85W
What will happens under the following scenarios -- different PSU ratings:
scenario 1:
Output voltage = 20V
Output current = 3.5A
Power = 70W
Answer: PI will work fine. max output of PSU will prevent excess current from entering PI
scenario 2:
Output voltage = 11.6V
Output current = 6A
Power = 69.6W
Answer: PI will get damaged. PI could draw more current (and the PSU will gladly supply this current since it's rated at 6A). If we are lucky current limiting fuse will prevent PI from getting damage.
scenario3:
Output voltage = 70V
Output current = 1A
Power = 70W
Answer: PI won't work. Not enough current supply can be delivered by the PSU. Potential for PSU to get damaged
scenario4:
Output voltage =5.1V
Output current = 13.7A
Power = 67.87W
Answer: PI will get damaged. PI could draw more current (and the PSU will gladly supply this current since it's rated at 6A). If we are lucky current limiting fuse will prevent PI from getting damage.
Are the answers to above scenarios correct?
In scenarios 1, 2, and 3 the Pi will be destroyed because the supply voltage is greater than 5V. In scenario 4 the Pi will be fine because the voltage is correct and even though the PSU is capable of supplying 13.7A the Pi will only draw what it needs, which is only a few amps.
Statistics: Posted by ame — Fri Aug 30, 2024 2:41 am